meyasmith meyasmith
  • 06-02-2018
  • Chemistry
contestada

The mole in 196.5 g of Zn(NO3)2

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faitharmour faitharmour
  • 06-02-2018
Zn(NO3)2 = 65.38+ 2{14+ 3(16)} = A
196.5 gr ^ 1/A = your answer mole

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