Respuesta :

Exvited
[tex]3(4x-2)=2(6x-3) \\ \\ 12x - 6 = 12x - 6 \\ \\ Answer: \fbox {Infinite Solutions} [/tex]
TSO
3(4x - 2) = 2(6x - 3)

12x - 6 = 12x - 6

Add 6 on both sides

12x = 12x

Divide by 12 on both sides

x = x

That means this has infinite solutions. Your answer is B.

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