A 1.0 × 103-kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the track is 1.0 × 102 meters. The magnitude of the car’s centripetal acceleration is

Respuesta :

Centripetal acceleration is given by:

[tex]a = \frac{v^{2}}{r} [/tex] where r is the radius, and v is the tangential velocity.

The diameter of the track is 100m, so the radius is 50m.

So, the acceleration is:

[tex]a = \frac{20^{2}}{50} = 8 m/s^{2}[/tex]