1a)Â
x1=vtÂ
x1=25*0.85=21.25 mÂ
1b)Â
a=v/tÂ
a=25/3.5=2.2 m/s^2Â
x=v^2/(2a)+x1Â
x=625/4.4+21.25=163.3 mÂ
c)Â
a=v/tÂ
a=25/3.5=2.2 m/s^2Â
2)Â
a=v/t=15/3.1=4.8 m/s^2Â
x1=v^2/(2a)Â
x1=225/9.6=23.4 m (while accelerating)Â
x2=vt=15*4500=67,500 mÂ
total distance isÂ
x=x1+x2=23.4+67,500=67,523.4 m =67.523 kmÂ