stacilammers
stacilammers
09-12-2017
Mathematics
contestada
factor by grouping 2u^3+3u^2-14u-21
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jdoe0001
jdoe0001
09-12-2017
[tex]\bf 2u^3+3u^2-14u-21\implies (2u^3+3u^2)-(14u+21) \\\\\\ u^2(2u+3)-7(2u+3)\implies \stackrel{\stackrel{common}{factor}}{(2u+3)}(u^2-7)[/tex]
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tynollette
tynollette
09-12-2017
(2u³+3u²)-(14u+21)
u²(2u+3)-7(2u+3)
(u²-7)(2u+3)
(u+√7)(u-√7)(2u+3)
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