Seudónimo
Seudónimo
10-11-2017
Mathematics
contestada
give right answer or else
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WojtekR
WojtekR
10-11-2017
[tex]A=\dfrac{1}{2}\cdot3\dfrac{3}{10}\cdot2\dfrac{6}{7}=\dfrac{1}{2}\cdot\dfrac{33}{10}\cdot\dfrac{20}{7}=\dfrac{1\cdot33\cdot20}{2\cdot10\cdot7}=\dfrac{1\cdot33\cdot20}{20\cdot7}=\dfrac{1\cdot33}{7}=\\\\\\=\dfrac{33}{7}=\boxed{4\dfrac{5}{7}}[/tex]
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