a concave mirror has the focal length equal to 0.927 m. to form a real image that is triple the size of the object on a screen, at what distance in front of the mirror should the object be placed (in m; answer a positive number)?

When it hits the concave mirror's reflecting surface, light converges at a single point and returns to the observer. It is sometimes referred to as a converging mirror for this reason.
Obtaining an enlarged, upright, and virtual image requires placing the concave mirror very close to the item.
A true and inverted image is created when the distance between the item and the mirror is increased, though the size of the image decreases.
The size and reality of the picture created by the concave mirror are also up for debate.

Given,

Focal length(f) = 0.927 m

Let the size of object is u,

Then according to question,

Size of image is 3u

For a concave mirror,

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

[tex]\frac{1}{0.927}[/tex] = [tex]\frac{1}{3u}[/tex] - [tex]\frac{1}{u}[/tex]

u = -0.618 m

Distance will never be in negative.

Hence, u= 0.618 m

To know more about concave mirror, visit:

https://brainly.com/question/3555871

#SPJ4