huyvo2003 huyvo2003
  • 10-06-2022
  • Mathematics
contestada

Help would be very much appreciated

Help would be very much appreciated class=

Respuesta :

konrad509
konrad509 konrad509
  • 10-06-2022

[tex]\dfrac{f(2+h)-f(2)}{h}=\dfrac{(2+h)^2+2(2+h)-1-(2^2+2\cdot2-1)}{h}=\\\\=\dfrac{4+4h+h^2+4+2h-1-(4+4-1)}{h}=\dfrac{h^2+6h+7-7}{h}=\dfrac{h^2+6h}{h}=h+6[/tex]

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