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If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation is y=-40x+58

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{15}{1.45} \: \: ft / sec[/tex]

Now we have to calculate the descent in 3.5 minutes ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{15}{1.45} \: \: \times 3.5 \times 60[/tex]

[tex]\qquad \sf  \dashrightarrow \: 2172.41 \: \: ft[/tex]

So, the airplane descends 2172.41 feels in three and a half minutes ~