The amount needed in Tina's account in order for her to reach her goal round to the nearest cent is given by: Option B: $866,442.02 approximately.
Suppose we're given that:
Then, we get:
[tex]P = \dfrac{r\times P_v}{1 - (1 + r)^{-n}}[/tex]
Why do we need this loan paying formula?
It is because we can simulate this situation with above condition.
Suppose the balance in her account is loan that she has given to someone. Let it be x, so [tex]P_v[/tex] = x dollars
The loan is increasing compoundly per year(here period of time is year wise). r = 2.2% = 0.022
That loan taker will pay off(since she need money only for 35 years) the loan in 35 years by giving $35756 = P payments each year.
We need to find the value of that initial loan amount (which refers to the amount that she needs to keep in her account).
Putting values in the aforesaid formula, we get:
[tex]P = \dfrac{r\times P_v}{1 - (1 + r)^{-n}}\\\\\\35756 = \dfrac{0.022 \times x}{1 - (1+0.022)^{-35}}\\\\\\x = \dfrac{35756 \times (1 - (1+0.022)^{-35})}{0.022} \approx 866442.02 \: \rm dollars[/tex]
Thus, the amount needed in Tina's account in order for her to reach her goal round to the nearest cent is given by: Option B: $866,442.02 approximately.
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