lisapressley2001
lisapressley2001
08-01-2017
Mathematics
contestada
Solve 4^3x=8 by graphing
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Tucon
Tucon
08-01-2017
[tex]\displaystyle\\ 4^{3x}=8 \\ \\ (2^2)^{3x}=2^3 \\ \\ 2^{2\times 3x} =2^3 \\ \\ 2^{6x} =2^3 \\ \\ 6x=3 \\ \\ x = \frac{3}{6} = \boxed{\frac{1}{2} }[/tex]
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