111003519 111003519

09-10-2021
Chemistry

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A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.350 M. How many grams of sodium bromide will he need to use?

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Liberty5078 Liberty5078

09-10-2021

Answer:

Explanation:

Molarity = moles/liters of solution

moles = molarity x Liters of solution

= 0.350 m/L x 0.855 L

= 0.299 mol

mass = moles x molar mass

= 0.299 mol x 102.89 g/ms

= 30.78 grams

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