contestada

What is the magnitude of the electric field strength at a point where an electron
experiences an electrostatic force of 8.3 x 10^-20 N?

Respuesta :

Luv2Teach

Answer:

Explanation:

Use the equation

[tex]E=\frac{q}{F}[/tex] where the charge, q, on the electron is 1.602 × [tex]10^{-19[/tex] :

[tex]E=\frac{1.602*10^{-19}}{8.3*10^{-20}}[/tex] so

E = 1.9 C/N