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A given line has the equation 2x 12y = −1. what is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

Respuesta :

Azieq
12y = - 2x - 1
y = - 1/6x - 1/12

- 1/6 × m2 = - 1
m2 = 6

9 = 6(0) + c
c = 9
y = 6x + 9

Answer:

A.

Step-by-step explanation:

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