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In ΔHIJ, the measure of ∠J=90°, HI = 88 feet, and IJ = 62 feet. Find the measure of ∠I to the nearest tenth of a degree.

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ujalakhan18

Answer:

[tex]\huge\boxed{\sf < I = 45.2\°}[/tex]

Step-by-step explanation:

Firstly, we've to draw a triangle according to the givens. (See the attached file)

Then according to the Trigonometric Ratios:

Cos (I) = Adjacent / Hypotenuse

Cos (I) = 62 / 88

Cos (I) = 0.704

< I = Cos ⁻¹ (0.704)

< I = 45.2°

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

Ver imagen ujalakhan18

Answer:

45.2

Step-by-step explanation:

hope it helps

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