adelaidegladebrooke adelaidegladebrooke
  • 08-01-2021
  • Mathematics
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How does 5 x(2)^n-1 simplify to 5/2 x (2)^n ?
Please help me

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sqdancefan
sqdancefan sqdancefan
  • 08-01-2021

9514 1404 393

Explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

__

  [tex]5\times2^{n-1}=5\times(2^n)(2^{-1})=5\times2^n\times\dfrac{1}{2}=\boxed{\dfrac{5}{2}\times2^n}[/tex]

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