Yanna11
Yanna11
07-10-2016
Mathematics
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Log3 9x^4 - log 3 (3x)^2
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apologiabiology
apologiabiology
07-10-2016
ok
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loga-logb=log(a/b)[tex]log_3(9x^4)-log_3(3x)^2= log_3\frac{9x^4}{(3x)^2} =log_3( \frac{9x^4}{9x^2})=log_3(x^2)=2log_3(x )[/tex]
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