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A tourist drops a rock from rest from a guardrail at an observatory point overlooking a valley. Calculate the velocity of the rock at the following times: a) 2.0 s b) 6.0 s 6. Determine the displacement for the rock in question 6 at

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Answer:

a) 19.6 m/s, 19.6 m

b) 58.8 m/s, 176.4 m

Explanation:

Take down to be positive.  Given:

v₀ = 0 m/s

a = 9.8 m/s²

a) Find v and Δy when t = 2.0 s.

v = at + v₀

v = (9.8 m/s²) (2.0 s) + 0 m/s

v = 19.6 m/s

Δy = v₀ t + ½ at²

Δy = (0 m/s) (2.0 s) + ½ (9.8 m/s²) (2.0 s)²

Δy = 19.6 m

b) Find v and Δy when t = 6.0 s.

v = at + v₀

v = (9.8 m/s²) (6.0 s) + 0 m/s

v = 58.8 m/s

Δy = v₀ t + ½ at²

Δy = (0 m/s) (6.0 s) + ½ (9.8 m/s²) (6.0 s)²

Δy = 176.4 m

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