A typical arteriole has a diameter of 0.080 mm and carries blood at the rate of 9.6 x10-5 cm3/s. What is the speed of the blood in (cm/s) the arteriole

Respuesta :

Answer:

v= 4.823 × 10⁻⁹ cm/s

Explanation:

given

flow rate = 9.6 x10-5 cm³/s, d = 0.080mm

r = d/2= 0.080/2= 0.0040 cm

speed = rate of blood flow × area

v = (9.6 x 10⁻⁵ cm³/s) × (πr²)

v = (9.6 x 10⁻⁵ cm³/s) × π(0.0040 × cm)²

v= 1.536 × 10⁻⁹π cm/s

v= 4.823 × 10⁻⁹ cm/s