Answer:
C. x = 6; straight vertical line
Step-by-step explanation:
you have the following equation in polar coordinates:
[tex]r=6sec(\theta)[/tex]
To find the equation in rectangular coordinates you take into account the following transformations:
[tex]r=\sqrt{x^2+y^2}\\\\x=rcos(\theta)\\\\[/tex]
Next, you replace and obtain:
[tex]r=6sec(\theta)\\\\r=\frac{6}{cos(\theta)}\\\\rcos(\theta)=6[/tex]
but, you have that x = rcos(θ), hence, x = 6
C. x = 6; straight vertical line
