ryanjcrooks2004 ryanjcrooks2004

13-05-2020
Mathematics

contestada

Special right triangles

Special right triangles class=

Respuesta :

khalil2012am khalil2012am

13-05-2020

Answer:

see down

Step-by-step explanation:

[tex]cos 60 = \frac{x}{6\sqrt{3} } \\x = 6\sqrt{3} * cos60\\x = 6\sqrt{3} * \frac{1}{2} \\x = 3\sqrt{3}[/tex]

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