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Polarizers #1 and #3 are "crossed" such that their transmission axes are perpendicular to each other. Polarizer #2 is placed between the polarizers #1 and #3 with its transmission axis at 60◦ with respect to the transmission axis of the polarizer #1 (see the sketch). #1 #2 #3 60◦ After passing through polarizer #2 the intensity I2 (in terms of the intermediate intensity I1) is

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Answer:

Explanation:

The angle between the polariser 1 and 2 is 60°

If I₁ be the intensity of light after polariser 1 , its intensity after polariser 2 that is I₂ can be expressed as follows

I₂ = I₁ cos² 60

= I₁ x 1/4

=  I₁ x [tex]\frac{1}{4}[/tex]

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