Answer:
Explanation:
Given
Length of each wire [tex]L=1.3\ m[/tex]
On wire A second harmonic frequency is given by
[tex]f_2_{a}=2\times (\frac{v}{2L})[/tex]
where f=frequency
v=velocity of wave
L=length of wire
[tex]v_a=f_2\times L[/tex]
[tex]v_a=640\times 1.3=832\ m/s[/tex]
For wire B third harmonic is given by
[tex]f_3_{b}=3\times (\frac{v}{2L})[/tex]
[tex]v_b=\frac{2L}{3}\cdot f_3_{b}[/tex]
[tex]v_b=\frac{2\times 1.3}{3}\times 640=554.66\ m/s[/tex]
