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A triangle with equal sides of length 14 cm has -2.5-nC charged objects at each corner.

Part A
Determine the direction of the electrical force exerted on the object at the top corner due to the two objects at the horizontal base of the triangle.

A) vertically downward
B) horizontally rightward
C) horizontally leftward
D) vertically upward

Part B
Determine the magnitude of the electrical force exerted on the object at the top corner due to the two objects at the base of the triangle.

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Poltergeist

Answer:

Part A: The correct answer is Choice D: vertically upward.

Part B: [tex]5.68*10^{-6}N[/tex]

Explanation:

Part A:

Since the three charges all all negative, the force is repulsive, and therefore the force on the object at the top corner is directed upward.

Part B:

The force on the charge at top corner is due to the charges at the other two corners.

[tex]F_{32}+F_{31}=2\frac{kQ^2}{d^2} = 2*\frac{8.9*10^9*(2.5*10^{-9})}{0.14^2}=\boxed{5.68*10^{-6}N}[/tex]

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