Answer:
Change in length=0.0275 m.
Explanation:
Given that
Length L= 56.5 m
Initial temperature ,T₁ = 24.7⁰C
Final temperature ,T₂ = -43.1 ⁰C
Coefficient of thermal expansion for steel taken as
α = 7.2 x 10⁻⁶ /⁰C
We know that change in the length due to change in the temperature given as
ΔL = Lα ΔT
ΔL =56.5 x 7.2 x 10⁻⁶ x (-43.1 -24.7 ) m
ΔL = - 27581.04 x 10⁻⁶ m
ΔL = -0.0275 m
Therefore the length of the steel get reduce by 0.0275 m.
The change in the length will be 0.0275 m.
