Respuesta :

HomertheGenius
cos (theta) =[tex] \frac{5}{13} [/tex] sec (theta) = [tex] \frac{1}{cos(theta)} = \frac{1}{ \frac{5}{13} }= \frac{13}{5} [/tex] sin(theta)=[tex] \sqrt{1- cos^{2}(theta) } = \sqrt{1 - \frac{25}{169} } = \sqrt{ \frac{144}{169} }=- \frac{12}{13} [/tex] cot(theta)=[tex] \frac{cos(theta)}{sin(theta}= \frac{ \frac{5}{13} }{ \frac{-12}{13} }= \frac{-5}{12} [/tex]