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An object of unknown mass m is hung from a vertical spring of unknown spring constant k, and the object is observed to be at rest when the spring has stretched by 17 cm . The object is then given a slight push upward and executes SHM. Determine period t of this oscillation

Respuesta :

Answer: Period is 0.827s

Explanation:

Given distance x= 17cm = 0.17m

We recall that Force F = k× x= k × 0.17m

We recall that F = M × g = M × 9.8

Equating both equations:

kx = mg

=> k/m = g/x

= 9.8/0.17 = 57.647

We also recall that ω = √(k/m)= 2πf = 2π/T.

√(k/m) = 7.593

=> T = 2π/7.593

Period T = 0.827s

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