iGot7
iGot7
06-04-2016
Chemistry
contestada
What volume will 20.0g of Argon occupy at STP?
Respuesta :
Willchemistry
Willchemistry
06-04-2016
Molar mass Argon = 39.948 g/mol
1 mol ------ 39.948 g
mol ----- 20.0 g
mol = 20.0 * 1 / 39.948
= 0.5006 moles
1 mol --------------------- 22.4 L ( at STP )
0.5006 moles ------------- L
L = 0.5006 * 22.4
=
11.21 L
hope this helps!
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