Respuesta :

[tex]\dfrac{8(4-z)}{7}=-z\\\\8(4-z)=-7z\\\\32-8z=-7z\\\\-7z+8z=32\\\\z=32[/tex]

8(4 - z)/ 7  = -z

8(4 - z) = -7z

32 - 8z = -7z

-8z + 7z = -32

-z = -32

z = 32