Respuesta :

abhi569


[tex] = > x + \frac{1}{3} = 9 [/tex]



[tex]\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,} [/tex]



[tex] = > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}[/tex]




Hence,


[tex]Value \: \: \: of \: \: x \: \: is \:
\frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}[/tex]

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