The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)
I have to write the equation of the line in standard form but I can't find out what kind of equation to write for this. Whoever can help me with this will get Brainliest.
Hello, 1) We must find the equation of the line RS: R=(-1;6)S=(5;5) y-6=(x+1)(5-6)/(5+1)y=-1/6*(x+1)+6 y=-x/6+35/6 Slope=-1/6 The perpendicular has the slope 6.
2) Find M the middle of [RS]M=((5-1)/2;(6+5)/2)=(2:11/2) 3) Equation of the perpendicular bisector: y-11/2=(x-2)*6y=6x-12+11/2 So y=6x-13/2 And sorry for my poor english
