The current is defined as the amount of charge Q that flows through a given point of a circuit in a given time [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t}[/tex]
In our problem, the time interval considered is
[tex]\Delta t= 2.9 h = 10440 s[/tex]
while the current is
[tex]I=5.8 A[/tex]
Therefore, if we re-arrange the previous equation, we can calculate the amount of charge that passes through the battery in that time:
[tex]Q=I \Delta t=(5.8 A)(10440 s)=6.05 \cdot 10^4 C[/tex]
